Orange-(A) (Inorganic compound) + H^{+} + H_2 | vedclass

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(A) The reaction of potassium dichromate $(K_2Cr_2O_7)$ with hydrogen peroxide $(H_2O_2)$ in an acidic medium produces chromium pentoxide $(CrO_5)$,wh

Vedclass · Accepted Answer

$6$

Vedclass · Answer

(A) The reaction of potassium dichromate $(K_2Cr_2O_7)$ with hydrogen peroxide $(H_2O_2)$ in an acidic medium produces chromium pentoxide $(CrO_5)$,which is blue in color.$K_2Cr_2O_7 + 4H_2O_2 + 2H^+ 	o 2CrO_5 + 5H_2O + 2K^+$In $CrO_5$,the chromium atom is bonded to four oxygen atoms via peroxide linkages $(-O-O-)$ and one double-bonded oxygen atom.The structure is a butterfly structure.Calculating the oxidation state of $Cr$ in $CrO_5$:Let the oxidation state be $x$.$x + 4(-1) + 1(-2) = 0$$x - 4 - 2 = 0$$x = +6$Thus,the oxidation state of the central atom $Cr$ in $CrO_5$ is $6$.

$Orange-(A)$ (Inorganic compound) $+ H^{+} + H_2O_2 \to Blue-(B)$. The oxidation state of the central atom in compound $(B)$ is:

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